使用BeautifulSoup查找包含特定文本的HTML标记

最后发布: 2009-05-14 21:46:12


问题

我正在尝试获取包含以下文本模式的HTML文档中的元素:#\\ S {11}

<h2> this is cool #12345678901 </h2>

所以,之前的匹配将使用:

soup('h2',text=re.compile(r' #\S{11}'))

结果将是这样的:

[u'blahblah #223409823523', u'thisisinteresting #293845023984']

我能够得到匹配的所有文本(见上面的行)。 但我希望文本的父元素匹配,因此我可以将其用作遍历文档树的起点。 在这种情况下,我希望返回所有h2元素,而不是文本匹配。

想法?

python regex beautifulsoup html-content-extraction
回答

from BeautifulSoup import BeautifulSoup
import re

html_text = """
<h2>this is cool #12345678901</h2>
<h2>this is nothing</h2>
<h1>foo #126666678901</h1>
<h2>this is interesting #126666678901</h2>
<h2>this is blah #124445678901</h2>
"""

soup = BeautifulSoup(html_text)


for elem in soup(text=re.compile(r' #\S{11}')):
    print elem.parent

打印:

<h2>this is cool #12345678901</h2>
<h2>this is interesting #126666678901</h2>
<h2>this is blah #124445678901</h2>


回答

text=用作标准而不是BeautifulSoup.Tag ,BeautifulSoup搜索操作提供[ BeautifulSoup.NavigableString对象的列表]。 检查对象的__dict__以查看可用的属性。 在这些属性中,由于BS4变化parentprevious更受青睐。

from BeautifulSoup import BeautifulSoup
from pprint import pprint
import re

html_text = """
<h2>this is cool #12345678901</h2>
<h2>this is nothing</h2>
<h2>this is interesting #126666678901</h2>
<h2>this is blah #124445678901</h2>
"""

soup = BeautifulSoup(html_text)

# Even though the OP was not looking for 'cool', it's more understandable to work with item zero.
pattern = re.compile(r'cool')

pprint(soup.find(text=pattern).__dict__)
#>> {'next': u'\n',
#>>  'nextSibling': None,
#>>  'parent': <h2>this is cool #12345678901</h2>,
#>>  'previous': <h2>this is cool #12345678901</h2>,
#>>  'previousSibling': None}

print soup.find('h2')
#>> <h2>this is cool #12345678901</h2>
print soup.find('h2', text=pattern)
#>> this is cool #12345678901
print soup.find('h2', text=pattern).parent
#>> <h2>this is cool #12345678901</h2>
print soup.find('h2', text=pattern) == soup.find('h2')
#>> False
print soup.find('h2', text=pattern) == soup.find('h2').text
#>> True
print soup.find('h2', text=pattern).parent == soup.find('h2')
#>> True


回答

使用bs4(Beautiful Soup 4),OP的尝试与预期完全一样:

from bs4 import BeautifulSoup
soup = BeautifulSoup("<h2> this is cool #12345678901 </h2>")
soup('h2',text=re.compile(r' #\S{11}'))

返回[<h2> this is cool #12345678901 </h2>]